In this Post, I am going to discuss how to* find the second largest number in array* in java.

So, without wasting time, let’s start

I am going to discuss the problem by using Java Collections. So, it is good for you to have knowledge of Java collections.

There is no any prerequisite for this problem except some patience to read. Have a copy and pen in your hand and start reading.

Table of Contents

## Problem [Second Largest Number in Array In Java]

Given an array of integers, our task is to write a program that efficiently finds the second largest element present in the array.

Input – arr = [1,23,43,52,11];

output – second largest element is 43.

Input – arr =[23,22,56,76,8,123]

output – second largest element is 76

*Solution – 1*

*Solution – 1*

This is the simplest method, all you need to sort the given element and return the second index if sorted in descending order or return second last index if sorted in ascending order

Time Complexity – O(n log(n))

Example – arr = [1,** 23**,4,56,7];

*Sorted arr = [1,4,7, 23,56] we return arr[3] as our answer.*

### Program –

*Note: No any element is repeated, If the element is repeated firstly add each element in sets then sort.*

```
// { Driver Code Starts
//Initial Template for Java
import java.io.*;
import java.util.*;
class Array {
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
while(t-- > 0)
{
int n = sc.nextInt();
int a[] = new int[n + 1];
for(int i=0;i<n;i++){
a[i] = sc.nextInt();
}
Solution ob = new Solution();
System.out.println(ob.print2largest(a,n));
}
}
}// } Driver Code Ends
class Solution
{
public static int print2largest(int A[],int N)
{
int arr[] = new int[N];
for(int i = 0;i<N; i++)
arr[i] = A[i];
Arrays.sort(arr);
return arr[N-2];
}
}
```

*Solution – 2*

*Solution – 2*

In this method, first we find the greatest element by single traversal and then we again traversed the whole array and then we will find the second greatest element

*Algorithm*

- Traverse the complete array and find first greatest element
- Again traverse the array and find second greatest element.

```
// Java program to find second largest
// element in an array
class GFG{
// Function to print the second largest elements
static void print2largest(int arr[], int arr_size)
{
int i, first, second;
// There should be atleast two elements
if (arr_size < 2)
{
System.out.printf(" Invalid Input ");
return;
}
int largest = second = Integer.MIN_VALUE;
// Find the largest element
for(i = 0; i < arr_size; i++)
{
largest = Math.max(largest, arr[i]);
}
// Find the second largest element
for(i = 0; i < arr_size; i++)
{
if (arr[i] != largest)
second = Math.max(second, arr[i]);
}
if (second == Integer.MIN_VALUE)
System.out.printf("There is no second " +
"largest element\n");
else
System.out.printf("The second largest " +
"element is %d\n", second);
}
// Driver code
public static void main(String[] args)
{
int arr[] = { 12, 35, 1, 10, 34, 1 };
int n = arr.length;
print2largest(arr, n);
}
}
```

These are the two ways to find the second largest number in the array in java. Comment in case of any queries. If you need the free version of this course then message on Instagram or mail us at [email protected] Learn Application of array.

he blog was how do i say it… relevant, finally something that helped me. Thanks